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How to Take the Square Root Of A Number In Elixir?

3 minutes read

To take the square root of a number in Elixir, you can use the :math.sqrt/1 function. Simply pass the number you want to find the square root of as an argument to this function. For example, to find the square root of 25, you can use :math.sqrt(25) which will return the value of 5.0.


How to find the square root of a range of numbers in Elixir?

To find the square root of a range of numbers in Elixir, you can use a combination of the Enum.map function and the :math.sqrt/1 function.


Here is an example code snippet that calculates the square root of each number in a range from 1 to 10:

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range = 1..10
square_roots = Enum.map(range, fn x -> :math.sqrt(x) end)

IO.inspect(square_roots)


This code creates a range from 1 to 10, then uses the Enum.map function to iterate over each number in the range and calculate its square root using the :math.sqrt/1 function. The result is stored in the square_roots variable, which is then printed using IO.inspect.


You can adjust the range values in the code snippet to calculate the square root of a different range of numbers if needed.


How to find the square root of an imaginary number in Elixir?

To find the square root of an imaginary number in Elixir, you can use the Complex module from the :ex_number library. Follow these steps to find the square root of an imaginary number:

  1. Add the :ex_number library to your mix.exs file:
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defp deps do
  [
    {:ex_number, "~> 0.3.0"}
  ]
end


  1. Run mix deps.get in your terminal to install the library.
  2. Use the Complex.sqrt/1 function to find the square root of an imaginary number. Here's an example code snippet: 
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i = Complex.sqrt(Complex.I)
IO.puts("Square root of imaginary number i: #{i}")


The above code snippet will output the square root of the imaginary number i in the form 0.5 + 0.5i. You can replace Complex.I with any imaginary number for which you want to find the square root.


What is the computational complexity of finding the square root in Elixir?

The computational complexity of finding the square root in Elixir is typically O(log n), where n is the number for which you are finding the square root. This complexity is based on algorithms such as Newton's method or binary search, which are commonly used for calculating square roots efficiently.


What is the limit of the square root function in Elixir?

The square root function in Elixir is part of the :math standard library module, which uses the Erlang :math module under the hood. The square root function in Elixir can handle floating-point numbers and will return the square root of the input number. The limit of the square root function in Elixir is based on the limitations of floating-point arithmetic in the underlying Erlang VM. The square root function should be able to handle most reasonable input numbers without issue, but for very large or very small numbers, there may be limitations in precision due to the nature of floating-point arithmetic.

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