How to Get an Index Of A List Element In Elixir?

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To get the index of a list element in Elixir, you can use the Enum.find_index/2 function. This function takes a list and a predicate function as arguments and returns the index of the first element in the list that matches the predicate. You can also use the Enum.with_index/1 function in combination with Enum.map/2 to get a list of tuples containing the index and element pairs. This allows you to easily access the index of any element in the list.


How to convert a list to a binary tree in Elixir?

Here's an example of how you can convert a list to a binary tree in Elixir:

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defmodule BinaryTree do
  defstruct value: nil, left: nil, right: nil

  def from_list([]), do: nil
  def from_list([head | tail]) do
    insert(head, from_list(tail))
  end

  def insert(value, nil), do: %BinaryTree{value: value}
  def insert(value, %BinaryTree{value: current_value, left: left, right: right}) when value <= current_value do
    %BinaryTree{value: current_value, left: insert(value, left), right: right}
  end
  def insert(value, %BinaryTree{value: current_value, left: left, right: right}) do
    %BinaryTree{value: current_value, left: left, right: insert(value, right)}
  end
end

list = [4, 2, 7, 1, 3, 6, 9]
tree = BinaryTree.from_list(list)
IO.inspect(tree)


In this code, we define a BinaryTree module with a from_list/1 function that takes a list as input and recursively inserts each element into the binary tree. The insert/2 function is responsible for inserting a new value into the correct position within the tree. Finally, we create a list of numbers and convert it to a binary tree using the from_list/1 function.


How to convert a list to a keyword list in Elixir?

To convert a list to a keyword list in Elixir, you can use the Enum.map function to transform each element of the list into a tuple where the first element is a keyword. Here's an example:

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list = [1, 2, 3]
keyword_list = Enum.map(list, fn x -> {:value, x} end)

IO.inspect(keyword_list)


In this example, list is the original list [1, 2, 3] and keyword_list is the transformed keyword list [{:value, 1}, {:value, 2}, {:value, 3}]. You can replace :value with any keyword you want to use.


How to convert a list of integers to a range in Elixir?

You can convert a list of integers to a range in Elixir using the Range.new function. Here's an example:

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list_of_integers = [1, 2, 3, 4, 5]
range = Range.new(Enum.min(list_of_integers), Enum.max(list_of_integers))

IO.inspect(range)


This will output:

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1..5


Alternatively, you can also use the :lists.seq function to generate a range of integers:

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list_of_integers = [1, 2, 3, 4, 5]
range = :lists.seq(Enum.min(list_of_integers), Enum.max(list_of_integers))

IO.inspect(range)


This will also output:

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[1, 2, 3, 4, 5]



How to pick random elements from a list in Elixir?

To pick random elements from a list in Elixir, you can use the Enum.random function along with the Enum.take function.


Here is an example code snippet that demonstrates how to pick 3 random elements from a list:

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list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
random_elements = Enum.take(Enum.shuffle(list), 3)

IO.inspect(random_elements)


In this code snippet, Enum.shuffle(list) randomly shuffles the elements in the list, and Enum.take(random_element, 3) picks the first 3 elements from the shuffled list. Finally, IO.inspect(random_elements) prints out the randomly selected elements.

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